• Infrared and Laser Engineering
  • Vol. 51, Issue 4, 20210549 (2022)
Xiaolei Li and Ming Gao
Author Affiliations
  • School of Ordnance Science and Technology, Xi'an Technological University, Xi'an 710021, China
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    DOI: 10.3788/IRLA20210549 Cite this Article
    Xiaolei Li, Ming Gao. Design of miniaturized dual-band observation system with composite aperture[J]. Infrared and Laser Engineering, 2022, 51(4): 20210549 Copy Citation Text show less

    Abstract

    Aiming at the shortcomings of single-band biological compound eye, such as small aperture, short line-of-sight and narrow receiving spectrum, a bionic compound eye optical system with large aperture for receiving visible light and medium-wave infrared was designed. In view of the large volume of the integrated optical path, the common optical path structure was selected for the sub-eye system. Based on the conjugate relation between object and image of entrance window and exit window, the geometric model of sub-eye system mosaic was established. By designing relay image transfer system, the curved image formed by sub-eye array was converted into planar image, which solved the problem of planar detector receiving curved image. The whole compound eye consists of 37 sub-eyes, with a focal length of 30 mm, a field of view of 20°, an entrance pupil of 10 mm, an included angle between the axes of adjacent sub-eyes of 16°, and a combined field of view of 116°. Compared with microlens array compound eye system, this curved bionic compound eye system has longer detection distance and more complete target information. The imaging quality of sub-eye system and receiving system is good, and there is no thermal difference in the temperature range of -40-+60 ℃.
    $ l1+l2+l3 = ΔϕR = 4RarcsinD4R+2Rarcsinp2R $(1)

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    $ \Delta \phi {\text{ = }}\frac{{D + p}}{R} $(2)

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    $ \left\{ ω0<Δϕ<2ω00<α<ω0 \right. $(3)

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    $ \left\{ ω0=α1+α1=α1ω1=α2+α2=α2 \right. $(4)

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    $ \Delta {\phi _i} = {\omega _{i - 1}} + {\omega _i} $(5)

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    $ \omega = {\omega _i} + \Delta {\phi _1} + \Delta {\phi _2} + \cdots {\text{ + }}\Delta {\phi _n} $(6)

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    $ \left( {m - 1} \right)\Delta \phi + 2{\omega _0} = 2\omega \geqslant {100^\circ } $(7)

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    $ \left\{ X=2LtanωixY=2Ltanωiy \right. $(8)

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    $ {W_{ix}} = \Delta {\varphi _i} + {\omega _{ix}} $(9)

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    $ \left\{ R=LsinWixC=2πLsinWix \right. $(10)

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    $ Ni = \frac{C}{Y} = \frac{{2\pi L\sin {W_{ix}}}}{Y} $(11)

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    $ \left\{ ωix=ωix=x2fωiy=ωiy=y2f \right. $(12)

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    $ Ni = \frac{{2\pi f'\left( {\Delta {\varphi _i} + \arctan \left( {\dfrac{x}{{2f'}}} \right)} \right)}}{y} $(13)

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    $ \left\{ (1h1ϕ)2i=1hi2ϕiχi=i=1aiLi(1h1ϕ)2i=1hi2ϕiθi=0i=1hiϕi=ϕ \right. $(14)

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    $ {x_{f,y}} = {\alpha _g} - \frac{1}{{n - {n_0}}}\left( {\frac{{{\rm{d}}n}}{{{\rm{d}}T}} - n\frac{{{\rm{d}}n{}_0}}{{{\rm{d}}T}}} \right) $(15)

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    $ {x_{f,d}} = 2{\alpha _g} + \frac{1}{n}\frac{{{\rm{d}}{n_0}}}{{{\rm{d}}T}} $(16)

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    $ \frac{R}{H} = \frac{{f'}}{{2c\mu }} $(17)

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    $ \psi = \frac{{1.22\lambda }}{D} $(18)

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    $ NITDij=λ1λ2{N(λ,TH)N(λ,TD)}λ1λ2N(λ,TMS)TA(λ)Rd(λ)Rd(λ)tjλ2Rj(λ)dλto(λ)dλσij $(19)

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