202 W dual-end-pumped Tm:YLF laser with a VBG as an output coupler

Disheng Wei; Shuyi Mi; Ke Yang; Junhui Li; Jinwen Tang; Baoquan Yao; Tongyu Dai; Xiaoming Duan

doi:10.1017/hpl.2021.37

Journals >High Power Laser Science and Engineering >Volume 9 >Issue 4 >Page 04000e48 > Article

High Power Laser Science and Engineering
Vol. 9, Issue 4, 04000e48 (2021)

202 W dual-end-pumped Tm:YLF laser with a VBG as an output coupler

Disheng Wei, Shuyi Mi, Ke Yang, Junhui Li, Jinwen Tang, Baoquan Yao^*, Tongyu Dai, and Xiaoming Duan

Author Affiliations

National Key Laboratory of Tunable Laser Technology, Harbin Institute of Technology, Harbin150001, China

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DOI: 10.1017/hpl.2021.37 Cite this Article Set citation alerts

Disheng Wei, Shuyi Mi, Ke Yang, Junhui Li, Jinwen Tang, Baoquan Yao, Tongyu Dai, Xiaoming Duan. 202 W dual-end-pumped Tm:YLF laser with a VBG as an output coupler[J]. High Power Laser Science and Engineering, 2021, 9(4): 04000e48 Copy Citation Text

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Abstract

We demonstrated a 202 W Tm:YLF slab laser using a reflecting volume Bragg grating (VBG) as an output coupler at room temperature. Two kinds of active heat dissipation methods were used for the VBG to suppress the shift of wavelength caused by its increasing temperature. The maximum continuous wave (CW) output power of 202 W using the microchannel cooling was obtained under the total incident pump power of 553 W, the corresponding slope efficiency and optical-to-optical conversion efficiency were 39.7% and 36.5%, respectively. The central wavelength was 1908.5 nm with the linewidth (full width at half maximum) of 0.57 nm. Meanwhile, with the laser output increasing from 30 to 202 W, the total shift was about 1.0 nm, and the wavelength was limited to two water absorption lines near 1908 nm. The beam quality factors M² were measured to be 2.3 and 4.0 in x and y directions at 202 W.

Keywords

hundred watt level reflecting volume Bragg grating Tm:YLF laser

\begin{align}{\lambda}_{\mathrm{B}}=2{n}_0\Lambda \sin {\theta}_{\mathrm{B}},\end{align}

((1))

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\begin{align}\frac{\mathrm{d}{\lambda}_{\mathrm{B}}}{\mathrm{d}T}=2\frac{\mathrm{d}{n}_0}{\mathrm{d}T}\Lambda +2\frac{\mathrm{d}\Lambda}{\mathrm{d}T}{n}_0={\lambda}_{\mathrm{B}}\cdot \left(\frac{1}{n}\frac{\mathrm{d}{n}_0}{\mathrm{d}T}+\rho \right).\end{align}

((2))