High efficiency sub-nanosecond electro–optical Q-switched laser operating at kilohertz repetition frequency

Xin Zhao; Zheng Song; Yuan-Ji Li; Jin-Xia Feng; Kuan-Shou Zhang

doi:10.1088/1674-1056/ab8ac4

Journals >Chinese Physics B >Volume 29 >Issue 8 >Page > Article

Chinese Physics B
Vol. 29, Issue 8, (2020)

High efficiency sub-nanosecond electro–optical Q-switched laser operating at kilohertz repetition frequency

Xin Zhao¹, Zheng Song¹, Yuan-Ji Li^1、2、†, Jin-Xia Feng^1、2, and Kuan-Shou Zhang^1、2

Author Affiliations

¹State Key Laboratory of Quantum Optics and Quantum Optics Devices, Institute of Opto-Electronics, Shanxi University, Taiyuan 030006, China

²Collaborative Innovation Center of Extreme Optics, Shanxi University, Taiyuan 030006, China

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DOI: 10.1088/1674-1056/ab8ac4 Cite this Article

Xin Zhao, Zheng Song, Yuan-Ji Li, Jin-Xia Feng, Kuan-Shou Zhang. High efficiency sub-nanosecond electro–optical Q-switched laser operating at kilohertz repetition frequency[J]. Chinese Physics B, 2020, 29(8): Copy Citation Text

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Abstract

Based on a theoretical model of Q-switched laser with the influences of the driving signal sent to the Pockels cell and the doping concentration of the gain medium taken into account, a method of achieving high energy sub-nanosecond Q-switched lasers is proposed and verified in experiment. When a Nd:YVO4 crystal with a doping concentration of 0.7 at.% is used as a gain medium and a driving signal with the optimal high-level voltage is applied to the Pockels cell, a stable single-transverse-mode electro–optical Q-switched laser with a pulse width of 0.77 ns and a pulse energy of 1.04 mJ operating at the pulse repetition frequency of 1 kHz is achieved. The precise tuning of the pulse width is also demonstrated.

Keywords

doping concentration of laser crystal kilohertz repetition frequency milijoule level sub-nanosecond laser tunable pulse width

$$ \begin{eqnarray}{\rm{d}}n/{\rm{d}}t=-\gamma nc{\sigma }_{{\rm{se}}}\phi,\end{eqnarray}$$

(1)

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$$ \begin{eqnarray}{\rm{d}}\phi /{\rm{d}}t=nc{\sigma }_{{\rm{se}}}\phi l/{l}_{{\rm{c}}}-\phi c\varepsilon /(2{l}_{{\rm{c}}}),\end{eqnarray}$$

(2)

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$$ \begin{eqnarray}{n}_{0}=\displaystyle \frac{{P}_{{\rm{in}}}{\tau }_{{\rm{f}}}[1-\exp (-\alpha l)]}{h{\nu }_{{\rm{p}}}}\left[1-\exp \left(-\displaystyle \frac{{T}_{{\rm{p}}}}{{\tau }_{{\rm{f}}}}\right)\right]\displaystyle \frac{{\omega }_{{\rm{l}}}^{2}}{{\omega }_{{\rm{pa}}}^{2}}\displaystyle \frac{1}{\pi {\omega }_{{\rm{pa}}}^{2}l},\end{eqnarray}$$

(3)

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$$ \begin{eqnarray}{\phi }_{0}={n}_{0}\displaystyle \frac{l}{c{\tau }_{{\rm{f}}}}\displaystyle \frac{{\rm{d}}\varOmega }{4\pi }\exp \left(\displaystyle \frac{\Delta t}{{\tau }_{{\rm{f}}}}\right),\end{eqnarray}$$

(4)

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$$ \begin{eqnarray}{\delta }_{{\rm{QS}}}(t)={\cos }^{2}\left(\displaystyle \frac{\pi }{2}\displaystyle \frac{V(t)}{{V}_{\lambda /4}}\right),\end{eqnarray}$$

(5)

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$$ \begin{eqnarray}\begin{array}{ll}\displaystyle \frac{V(t)}{{V}_{\lambda /4}}= & \displaystyle \frac{{V}_{{\rm{hl}}}}{{V}_{\lambda /4}}{\left(1-\exp \left[-{\left(\displaystyle \frac{t}{{t}_{{\rm{qr}}}}\right)}^{4}\right]\right)}^{4}\\ & \times \exp \left[-{\left(\displaystyle \frac{t-{t}_{{\rm{qs}}}/2}{{t}_{{\rm{qs}}}}\right)}^{400}\right],\end{array}\end{eqnarray}$$

(6)

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