Amplification of 200-ps high-intensity laser pulses via frequency matching stimulated Brillouin scattering

Hang Yuan; Yulei Wang; Qiang Yuan; Dongxia Hu; Can Cui; Zhaohong Liu; Sensen Li; Yi Chen; Feng Jing; Zhiwei Lü

doi:10.1017/hpl.2019.31

Journals >High Power Laser Science and Engineering >Volume 7 >Issue 3 >Page 03000e41 > Article

High Power Laser Science and Engineering
Vol. 7, Issue 3, 03000e41 (2019)

Amplification of 200-ps high-intensity laser pulses via frequency matching stimulated Brillouin scattering

Hang Yuan¹, Yulei Wang^1、3、†, Qiang Yuan², Dongxia Hu², Can Cui¹, Zhaohong Liu¹, Sensen Li¹, Yi Chen¹, Feng Jing², and Zhiwei Lü^1、3、†

Author Affiliations

¹National Key Laboratory of Science and Technology on Tunable Laser, Harbin Institute of Technology, Harbin 150080, China

²Laser Fusion Research Center, China Academy of Engineering Physics, Mianyang 621900, China

³School of Electronic and Information Engineering, Hebei University of Technology, Tianjin 300401, China

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DOI: 10.1017/hpl.2019.31 Cite this Article Set citation alerts

Hang Yuan, Yulei Wang, Qiang Yuan, Dongxia Hu, Can Cui, Zhaohong Liu, Sensen Li, Yi Chen, Feng Jing, Zhiwei Lü. Amplification of 200-ps high-intensity laser pulses via frequency matching stimulated Brillouin scattering[J]. High Power Laser Science and Engineering, 2019, 7(3): 03000e41 Copy Citation Text

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Abstract

Laser pulses of 200 ps with extremely high intensities and high energies are sufficient to satisfy the demand of shock ignition, which is an alternative path to ignition in inertial confinement fusion (ICF). This paper reports a type of Brillouin scheme to obtain high-intensity 200-ps laser pulses, where the pulse durations are a challenge for conventional pulsed laser amplification systems. In the amplification process, excited Brillouin acoustic waves fulfill the nonlinear optical effect through which the high energy of a long pump pulse is entirely transferred to a 200-ps laser pulse. This method was introduced and achieved within the SG-III prototype system in China. Compared favorably with the intensity of $2~\text{GW}/\text{cm}^{2}$ in existing ICF laser drivers, a 6.96-$\text{GW}/\text{cm}^{2}$ pulse with a width of 170 ps was obtained in our experiment. The practical scalability of the results to larger ICF laser drivers is discussed.

Keywords

frequency matching high-intensity laser pulse stimulated Brillouin scattering

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$$\begin{eqnarray}\displaystyle & \displaystyle -\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}z}+\frac{n}{c}\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}t}=\frac{i\unicode[STIX]{x1D714}_{\text{S}}\unicode[STIX]{x1D6FE}}{2nc\unicode[STIX]{x1D70C}_{0}}\unicode[STIX]{x1D70C}^{\ast }E_{\text{L}}, & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle \frac{\unicode[STIX]{x2202}^{2}\unicode[STIX]{x1D70C}}{\unicode[STIX]{x2202}t^{2}}-(2i\unicode[STIX]{x1D714}-\unicode[STIX]{x1D6E4}_{\text{B}})\frac{\unicode[STIX]{x2202}\unicode[STIX]{x1D70C}}{\unicode[STIX]{x2202}t}-(i\unicode[STIX]{x1D714}\unicode[STIX]{x1D6E4}_{\text{B}})\unicode[STIX]{x1D70C}=\frac{\unicode[STIX]{x1D6FE}}{4\unicode[STIX]{x03C0}}q_{\text{B}}^{2}E_{\text{L}}E_{\text{S}}^{\ast }. & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle \unicode[STIX]{x1D70C}(z,t) & = & \displaystyle \frac{\unicode[STIX]{x1D6FE}q_{\text{B}}^{2}}{4\unicode[STIX]{x03C0}\unicode[STIX]{x1D6FA}_{\text{B}}}\frac{1}{\sqrt{2\unicode[STIX]{x03C0}}}\int _{-\infty }^{t}f(t-\unicode[STIX]{x1D70F})E_{\text{L}}(z,\unicode[STIX]{x1D70F})E_{\text{S}}^{\ast }(z,\unicode[STIX]{x1D70F})\,\text{d}\unicode[STIX]{x1D70F},\nonumber\\ \displaystyle & & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle f(t) & = & \displaystyle \frac{-\sqrt{2\unicode[STIX]{x03C0}}\unicode[STIX]{x1D6FA}_{\text{B}}\exp [-(\unicode[STIX]{x1D6E4}_{\text{B}}/2)t]}{\sqrt{\unicode[STIX]{x1D6FA}_{\text{B}}-\frac{\unicode[STIX]{x1D6E4}_{\text{B}}^{2}}{4}t}}\exp (i\unicode[STIX]{x1D6FA}_{\text{B}}t)\nonumber\\ \displaystyle & & \displaystyle \times \,\sin \left(\sqrt{\unicode[STIX]{x1D6FA}_{\text{B}}-\frac{\unicode[STIX]{x1D6E4}_{\text{B}}^{2}}{4}}t\right),\quad t\geqslant 0.\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle \frac{\unicode[STIX]{x2202}E_{\text{L}}}{\unicode[STIX]{x2202}z}+\frac{n}{c}\frac{\unicode[STIX]{x2202}E_{\text{L}}}{\unicode[STIX]{x2202}t}=-ig\unicode[STIX]{x1D710}E_{\text{S}},\quad & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle -\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}z}+\frac{n}{c}\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}t}=-ig\unicode[STIX]{x1D710}^{\ast }E_{\text{L}},\quad & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle \unicode[STIX]{x1D710}(z,t)=\frac{1}{\sqrt{2\unicode[STIX]{x03C0}}}\int _{-\infty }^{t}f(t-\unicode[STIX]{x1D70F})E_{\text{L}}(z,\unicode[STIX]{x1D70F})E_{\text{S}}^{\ast }(z,\unicode[STIX]{x1D70F})\,\text{d}\unicode[STIX]{x1D70F}.\quad & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle \frac{\unicode[STIX]{x2202}E_{\text{L}}}{\unicode[STIX]{x2202}z}+\frac{n}{c}\frac{\unicode[STIX]{x2202}E_{\text{L}}}{\unicode[STIX]{x2202}t}=-ig\unicode[STIX]{x1D710}E_{\text{S}}-\frac{\unicode[STIX]{x1D6FC}}{2}E_{\text{L}}-\frac{\unicode[STIX]{x1D6FD}}{4}E_{\text{L}}^{2},\quad & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle & \displaystyle -\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}z}+\frac{n}{c}\frac{\unicode[STIX]{x2202}E_{\text{S}}}{\unicode[STIX]{x2202}t}=-ig\unicode[STIX]{x1D710}^{\ast }E_{\text{L}}-\frac{\unicode[STIX]{x1D6FC}}{2}E_{\text{S}}-\frac{\unicode[STIX]{x1D6FD}}{4}E_{\text{S}}^{2},\quad & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle \frac{P_{\text{th}}}{P_{0}}=\frac{1}{\max [J_{n}^{2}(\unicode[STIX]{x1D6FE})]}, & & \displaystyle\end{eqnarray}$$

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$$\begin{eqnarray}\displaystyle l_{\text{eff}}=\left\{\begin{array}{@{}ll@{}}\frac{d}{2\sin \big(\frac{\unicode[STIX]{x1D703}}{2}\big)}, & l_{m}\leqslant l,\\ \frac{d-d\Big[1-\frac{l\sin \big(\frac{\unicode[STIX]{x1D703}}{2}\big)}{d}\Big]^{2}}{2\sin \big(\frac{\unicode[STIX]{x1D703}}{2}\big)}, & l_{m}>l,\end{array}\right. & & \displaystyle\end{eqnarray}$$

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