• Chinese Physics B
  • Vol. 29, Issue 10, (2020)
Pengdi Wang1 and Xianghua Zeng1、2、†
Author Affiliations
  • 1College of Physics Science and Technology & Institute of Optoelectronic Technology, Yangzhou University, Yangzhou 225002, China
  • 2College of Electrical, Energy and Power Engineering, Yangzhou University, Yangzhou 517, China
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    DOI: 10.1088/1674-1056/abab70 Cite this Article
    Pengdi Wang, Xianghua Zeng. High efficient Al: ZnO based bifocus metalens in visible spectrum[J]. Chinese Physics B, 2020, 29(10): Copy Citation Text show less

    Abstract

    The optical components of the visible light band are widely used in daily life and industrial development. However due to the serious loss of light and the high cost, the application is limited. The broadband gap metasurface will change this situation due to its low absorption and high efficiency. Herein, we simulate a size-adjustable metasurface of the Al doped ZnO (AZO) nanorod arrays based on finite difference time domain method (FDTD) which can realize the conversion of amplitude polarization and phase in the full visible band. The corresponding theoretical polarization conversion efficiency can reach as high as 91.48% (450 nm), 95.27% (530 nm), and 91.01% (65 nm). The modulation of focusing wavelength can be realized by directly adjusting the height of the AZO nanorod. The designed half-wave plate and metalens can be applied in the imaging power modulation halfwave conversion and enriching the spectroscopy.
    $$ \begin{eqnarray}\begin{array}{ll} & {E}_{{\rm{out}}}=T(\theta )\left[\begin{array}{c}1\\ \pm {\rm{i}}\end{array}\right]={{\rm{e}}}^{\pm {\rm{i}}2\theta }\left[\begin{array}{c}1\\ \mp {\rm{i}}\end{array}\right],\end{array}\end{eqnarray}$$(1)

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    $$ \begin{eqnarray}T(\theta )=\left[\begin{array}{cc}\cos 2\theta & \sin 2\theta \\ -\sin 2\theta & -\cos 2\theta \end{array}\right].\end{eqnarray}$$(2)

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    $$ \begin{eqnarray}\theta =\displaystyle \frac{\pi }{\lambda }\left(\sqrt{{f}^{2}+{x}^{2}}-f\right).\end{eqnarray}$$(3)

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    $$ \begin{eqnarray}\theta =\displaystyle \frac{\pi }{\lambda }\left(\sqrt{{f}^{2}+{x}^{2}+{y}^{2}}-f\right).\end{eqnarray}$$(4)

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    $$ \begin{eqnarray}\phi =\displaystyle \frac{2\pi }{\lambda }\left(\sqrt{{f}^{2}+{x}^{2}+{y}^{2}}-f\right)=2\theta .\end{eqnarray}$$(5)

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    Pengdi Wang, Xianghua Zeng. High efficient Al: ZnO based bifocus metalens in visible spectrum[J]. Chinese Physics B, 2020, 29(10):
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